3x^2+66x-272=0

Solution for 3x^2+66x-272=0 equation:

3x^2+66x-272=0

a = 3; b = 66; c = -272;
Δ = b2-4ac
Δ = 662-4·3·(-272)
Δ = 7620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7620}=\sqrt{4*1905}=\sqrt{4}*\sqrt{1905}=2\sqrt{1905}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-2\sqrt{1905}}{2*3}=\frac{-66-2\sqrt{1905}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+2\sqrt{1905}}{2*3}=\frac{-66+2\sqrt{1905}}{6}
$